Quack 1,568 Posted August 29, 2016 Report Share Posted August 29, 2016 Like if youre given degrees or coordinates? Ex. 150° find all 6 trig functions (sin, cos, tan, cot, sec, csc) And..... (-7, 24) find all 6 trig functions? Explain it plZzZzZ Quote Link to post Share on other sites
Shawnic 2,977 Posted August 29, 2016 Report Share Posted August 29, 2016 I'm not sure I understand what you're asking for. Do you mean like if you're given 150 degrees, to find sin (150) , cos(150) etc.? Also, what do you mean by the coordinates thing? Are you asking for the trig function of the angle made by the position vector of that point? Quote Link to post Share on other sites
Archie 1,560 Posted August 29, 2016 Report Share Posted August 29, 2016 You don't 1 Quote Link to post Share on other sites
Quack 1,568 Posted August 29, 2016 Author Report Share Posted August 29, 2016 24 minutes ago, Master Flap said: I'm not sure I understand what you're asking for. Do you mean like if you're given 150 degrees, to find sin (150) , cos(150) etc.? Also, what do you mean by the coordinates thing? Are you asking for the trig function of the angle made by the position vector of that point? You know what? Ill tell u the questions since i didnt make things clear. Given a point on the terminal side of an angle, find all 6 trig functions: (-7, 24) And Find all 6 trig functions for the given angles: 150° Quote Link to post Share on other sites
Shawnic 2,977 Posted August 29, 2016 Report Share Posted August 29, 2016 9 minutes ago, Quack said: You know what? Ill tell u the questions since i didnt make things clear. Given a point on the terminal side of an angle, find all 6 trig functions: (-7, 24) And Find all 6 trig functions for the given angles: 150° Yeah, that's what I thought. For the first one, find the slope the point makes with the origin. In this case, (-7-0)/(24-0) = -7/24 Then you draw a right angled triangle with the slope and the x axis. You know that tan is opposite side/ adjacent side so you can assume the sides of the triangle to be 7k and 24 k where k is a constant. Using Pythagoras theorem, we find the third side as 25k. Now use the definition of trig ratios to get the functions in that triangle. Well, just express 150 as a standard trig angle. E.g 150 = 90 +60. So, sin (150) = sin (90 + 60) But sin(90 +x) = cos(x) Therefore sin(150) = cos (60) = 1/2 2 Quote Link to post Share on other sites
Conan Edogawa 837 Posted August 29, 2016 Report Share Posted August 29, 2016 [RESERVED] Will post solution. Quote Link to post Share on other sites
Liberty 2,305 Posted August 30, 2016 Report Share Posted August 30, 2016 I got super excited because someone asked a question I could finally answer but then I saw Shawn answered it... Remember when doing the trig functions that the secant, cosecant, and co tangent are the reciprocals and you should be fine. Oh also, I used to always confuse which function secant and cosecant went to because its COsecant and then just plain secant but if you just remember it's different than what you'd expect than it's easy to remember. This post is kinda pointless but I wanted to say something because of how excited I got.... 4 Quote Link to post Share on other sites
Quack 1,568 Posted August 30, 2016 Author Report Share Posted August 30, 2016 15 hours ago, Liberty said: I got super excited because someone asked a question I could finally answer but then I saw Shawn answered it... Remember when doing the trig functions that the secant, cosecant, and co tangent are the reciprocals and you should be fine. Oh also, I used to always confuse which function secant and cosecant went to because its COsecant and then just plain secant but if you just remember it's different than what you'd expect than it's easy to remember. This post is kinda pointless but I wanted to say something because of how excited I got.... lol! yeah, i used to mix them up but i dont anymore! cuz ya just gotta remember: "There cant be 2 CO's" 1 Quote Link to post Share on other sites
Liberty 2,305 Posted August 31, 2016 Report Share Posted August 31, 2016 5 hours ago, Quack said: lol! yeah, i used to mix them up but i dont anymore! cuz ya just gotta remember: "There cant be 2 CO's" Yeah, it still confuses me a bit.. We're doing all 6 trig functions on the unit circle with degrees and radians in math right now and I'm actually super confused. :') In my defense, I was out a week from school because I was sick.. Quote Link to post Share on other sites
Quack 1,568 Posted August 31, 2016 Author Report Share Posted August 31, 2016 10 hours ago, Liberty said: Yeah, it still confuses me a bit.. We're doing all 6 trig functions on the unit circle with degrees and radians in math right now and I'm actually super confused. :') In my defense, I was out a week from school because I was sick.. Its actually pretty easy. I'm sure you'll get the hang of it Quote Link to post Share on other sites
Shawnic 2,977 Posted August 31, 2016 Report Share Posted August 31, 2016 16 hours ago, Liberty said: Yeah, it still confuses me a bit.. We're doing all 6 trig functions on the unit circle with degrees and radians in math right now and I'm actually super confused. :') In my defense, I was out a week from school because I was sick.. I used to struggle with trigonometry quite a bit when I initially learnt it. But after I understood the actual significance of the ratios and the notation, it was as easy as multiplication tables. 1 Quote Link to post Share on other sites
Liberty 2,305 Posted September 1, 2016 Report Share Posted September 1, 2016 On August 31, 2016 at 7:23 AM, Quack said: Its actually pretty easy. I'm sure you'll get the hang of it On August 31, 2016 at 0:55 PM, Master Flap said: I used to struggle with trigonometry quite a bit when I initially learnt it. But after I understood the actual significance of the ratios and the notation, it was as easy as multiplication tables. Yeah I'm already starting to, missing a week of school threw me off Quote Link to post Share on other sites
Jazlyn 522 Posted October 23, 2018 Report Share Posted October 23, 2018 On 8/31/2016 at 9:55 AM, Master Flap said: I used to struggle with trigonometry quite a bit when I initially learnt it. But after I understood the actual significance of the ratios and the notation, it was as easy as multiplication tables. even multiplication tables are hard for me.smh Quote Link to post Share on other sites
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