Help/Tutoring Thread

[Sky 101]

12 hours ago, Laplace Distribution said:

To simplify a square root, You divide it up into a square number * a number such as sqrt(200) = sqrt (100*2) or 10  * sqrt(2).

oh oh. I get that now  Thanks! 

[Conan Edogawa 837]

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[Archie 1,560]

1. If a^x = b, b^y = c, c^z = a, prove that xyz = 1.

2. If x = 3 + sqrt(8), find x^4 + 1/x^4.

3. If 2^(x+1) .3^(y-1) = (2.3)^5, find the value of 2x+y.

4. If x = [sqrt(3) - sqrt(2)] / [sqrt(3) + sqrt(2)] and y = [sqrt(3) + sqrt(2)] / [sqrt(3) - sqrt(2)], find the value of x^2 + xy + y^2.

..yeah im done

Edited May 7, 2016 by Black Widow

[Conan Edogawa 837]

4 hours ago, Black Widow said:

1. If a^x = b, b^y = c, c^z = a, prove that xyz = 1.

2. If x = 3 + sqrt(8), find x^4 + 1/x^4.

3. If 2^(x+1) .3^(y-1) = (2.3)^5, find the value of 2x+y.

4. If x = [sqrt(3) - sqrt(2)] / [sqrt(3) + sqrt(2)] and y = [sqrt(3) + sqrt(2)] / [sqrt(3) - sqrt(2)], find the value of x^2 + xy + y^2.

..yeah im done

 b=a^x 
b^y=(a^x)y 
b^y=a^xy 
b^y=c^z 
b^y=a^xy 
a^xy=c^z 
c^z=a 
(a^xy)^z=a 
a^xyz=a 
xyz=1.

Also

 If x = 3 + sqrt(8), find x^4 + 1/x^4.

Is this 1/(x^4), or (1/x)^4???

Edited May 7, 2016 by Laplace Distribution

[Archie 1,560]

3 hours ago, Laplace Distribution said:

 b=a^x 
b^y=(a^x)y 
b^y=a^xy 
b^y=c^z 
b^y=a^xy 
a^xy=c^z 
c^z=a 
(a^xy)^z=a 
a^xyz=a 
xyz=1.

Also

 If x = 3 + sqrt(8), find x^4 + 1/x^4.

Is this 1/(x^4), or (1/x)^4???

Thanks!

1/(x^4).