How would you solve questions like these?


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Im kinda confused about these:

 

Use a calculator to find all solutions. (Let k represent an arbitrary integer. Round your answers to four decimal places.)

sin(x) = 0.48
x= ________________ ±2πk   (solution with the terminal side of x in the third quadrant)
x= ________________ ±2πk   (solution with the terminal side of x in the fourth quadrant)
 
also one like this:
 
Use a calculator to find all solutions to four decimal places. (Let k represent an arbitrary integer. Round your answers to four decimal places.)
cos(x) = 0.77
x= _________________ ±2πk     (solution with the terminal side of x in the first quadrant)
x= _________________ ±2πk     (solution with the terminal side of x in the fourth quadrant)
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It's easy. You know that trigonometric functions likes sine and cosine have periods of 2π, i.e. they repeat their values after 2π. so sin(x) = sin(2π +x) = sin (4π + x) = sin(2πk + x) where k is an integer. 

You know inverse trigonometry, right? If sin(x)  = -0.48, Using your calculator, find what principal value of x (value of x from -π to π) gives -0.48. In other words, find sin-1 (-0.48) or arcsin(-0.48) 

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23 hours ago, Master Flap said:

It's easy. You know that trigonometric functions likes sine and cosine have periods of 2π, i.e. they repeat their values after 2π. so sin(x) = sin(2π +x) = sin (4π + x) = sin(2πk + x) where k is an integer. 

You know inverse trigonometry, right? If sin(x)  = -0.48, Using your calculator, find what principal value of x (value of x from -π to π) gives -0.48. In other words, find sin-1 (-0.48) or arcsin(-0.48) 

@Quack Obviously this didn't help. :P 

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